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13x^2-51x-60=0
a = 13; b = -51; c = -60;
Δ = b2-4ac
Δ = -512-4·13·(-60)
Δ = 5721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-51)-\sqrt{5721}}{2*13}=\frac{51-\sqrt{5721}}{26} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-51)+\sqrt{5721}}{2*13}=\frac{51+\sqrt{5721}}{26} $
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